Saturday

January 31, 2015

January 31, 2015

Posted by **Morgan** on Saturday, November 5, 2011 at 2:09am.

- Physics -
**drwls**, Saturday, November 5, 2011 at 6:03amThe initial kinetic energy before it starts climbing is

KEmax = (1/2)MV^2 + (1/2)I*w^2

where I = M R^2 and w = V/R.

I is the moment of intertia, R is the radius, V is the initial velocity and and w is the initial angular velocity.

Combining terms,

KEmax = M V^2.

It stops rolling when

KEmax = M g h,

the potential energy increase.

h = V^2/g. The ramp angle, hoop mass and radius do not matter.

**Answer this Question**

**Related Questions**

Physics - A 1-kg thin hoop with a 50-cm radius rolls down a 47° slope without ...

Physics - A 1-kg thin hoop with a 50-cm radius rolls down a 47° slope without ...

physics - As part of a kinetic sculpture, a 5.6 kg hoop with a radius of 3.8 m ...

science - A hoop of mass M = 4 kg and radius R = 0.4 m rolls without slipping ...

Physics - A hoop of mass M = 3 kg and radius R = 0.5 m rolls without slipping ...

science - A hoop of mass M = 4 kg and radius R = 0.4 m rolls without slipping ...

physics - A spherically symmetric object, with radius R = 0.50 m and mass M = 1....

Physics - A 190 kg hoop rolls along a horizontal floor so that the hoop's center...

physics' - A 100 kg hoop rolls along a horizontal floor so that the hoop's ...

Physics - An green hoop with mass mh = 2.4 kg and radius Rh = 0.14 m hangs from ...