Posted by **Morgan** on Saturday, November 5, 2011 at 2:09am.

15. [1pt] A thin hoop of radius r = 0.59 m and mass M = 9.2 kg rolls without slipping across a horizontal floor with a velocity v = 3.3 m/s. It then rolls up an incline with an angle of inclination θ = 31°. What is the maximum height h reached by the hoop before rolling back down the incline?

- Physics -
**drwls**, Saturday, November 5, 2011 at 6:03am
The initial kinetic energy before it starts climbing is

KEmax = (1/2)MV^2 + (1/2)I*w^2

where I = M R^2 and w = V/R.

I is the moment of intertia, R is the radius, V is the initial velocity and and w is the initial angular velocity.

Combining terms,

KEmax = M V^2.

It stops rolling when

KEmax = M g h,

the potential energy increase.

h = V^2/g. The ramp angle, hoop mass and radius do not matter.

## Answer This Question

## Related Questions

- Physics - A 1-kg thin hoop with a 50-cm radius rolls down a 47° slope without ...
- Physics - A 1-kg thin hoop with a 50-cm radius rolls down a 47° slope without ...
- physics - As part of a kinetic sculpture, a 5.6 kg hoop with a radius of 3.8 m ...
- physics - A spherically symmetric object, with radius R = 0.700 m and mass M = 1...
- science - A hoop of mass M = 4 kg and radius R = 0.4 m rolls without slipping ...
- physics - A spherically symmetric object, with radius R = 0.50 m and mass M = 1....
- PHYSICS - A spherically symmetric object with radius of .7m and mass of 1.6kg ...
- Physics - A 190 kg hoop rolls along a horizontal floor so that the hoop's center...
- physics' - A 100 kg hoop rolls along a horizontal floor so that the hoop's ...
- Physics - A hoop starts from rest at a height 3.0 m above the base of an ...

More Related Questions