Posted by John on .
The perimeter of a rectangle is 122m. The length of the rectangle is 11m less than 5 times the width. Find the dimensions of the rectangle.

Algebra 2 
Bosnian,
P = Perimeter
L = Length
W = Width
P = 2 L + 2 W
P = 2 ( L + W )
P = 122 m
L = 5 W  11
122 = 2 ( 5 W  11 + W )
122 = 2 ( 6 W  11 )
122 = 12 W  22
122 + 22 = 12 W
12 W = 144 Diwidw both sides with 12
W = 144 / 12
W = 12 m
L = 5 W  11
L = 5 * 12  11
L = 60  11
L = 49 m
P = 2 ( L + W )
P = 2 ( 49 + 12 )
P = 2 * 61
P = 122 m