Physics (College)
posted by Set8 on .
A car starts from rest at a stop sign. It accelerates at 2.0 m/s^2for 6.0 seconds, coasts for 2.0 s, and then slows down at a rate of 1.5 m/s^2 for the next stop sign.
How far apart are the stop signs?

divide it into three parts.
part one: acceleration.
find vf from a*t then find distance
part two: constant velocity
you know v, d=v*t
part three:
you know vi, vf, and a. Find distance
vf^2=vi^2+2ad
add the three distances 
108

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