Posted by Set8 on Friday, November 4, 2011 at 9:49pm.
A car starts from rest at a stop sign. It accelerates at 2.0 m/s^2for 6.0 seconds, coasts for 2.0 s, and then slows down at a rate of 1.5 m/s^2 for the next stop sign.
How far apart are the stop signs?

Physics (College)  bobpursley, Friday, November 4, 2011 at 10:42pm
divide it into three parts.
part one: acceleration.
find vf from a*t then find distance
part two: constant velocity
you know v, d=v*t
part three:
you know vi, vf, and a. Find distance
vf^2=vi^2+2ad
add the three distances

Physics (College)  Anonymous, Sunday, October 19, 2014 at 12:14am
108

Physics (College)  Bob Dylan, Wednesday, January 25, 2017 at 2:09am
36
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