Posted by **Set8** on Friday, November 4, 2011 at 9:49pm.

A car starts from rest at a stop sign. It accelerates at 2.0 m/s^2for 6.0 seconds, coasts for 2.0 s, and then slows down at a rate of 1.5 m/s^2 for the next stop sign.

How far apart are the stop signs?

- Physics (College) -
**bobpursley**, Friday, November 4, 2011 at 10:42pm
divide it into three parts.

part one: acceleration.

find vf from a*t then find distance

part two: constant velocity

you know v, d=v*t

part three:

you know vi, vf, and a. Find distance

vf^2=vi^2+2ad

add the three distances

- Physics (College) -
**Anonymous**, Sunday, October 19, 2014 at 12:14am
108

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