Posted by **Megan** on Friday, November 4, 2011 at 3:17pm.

Two hoses are connected to a swimming pool. Working together, they can fill the pool in 4 hr. The larger hose, working alone, can fill the pool in 6 hr less time than the smaller one. How long would it take the smaller one, woking alone, to fill the pool?

Please explain

- Algebra -
**Steve**, Saturday, November 5, 2011 at 5:36pm
If small = s, big = b, sb = both, then

1/sb = 1/s + 1/b

1/4 = 1/s + 1/6

1/12 = 1/s

s = 12 hours

- Algebra -
**Megan**, Saturday, November 5, 2011 at 9:59pm
Thank you!

- Algebra -
**Steve**, Sunday, November 6, 2011 at 6:11am
Yeah. Too bad I did it wrong. I read "6 hours" rather than "6 hours less".

It's been done correctly later on.

- Algebra -
**Steve**, Sunday, November 6, 2011 at 6:13am
See the solution to the problem posted Nov 5 at 10:18 pm

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