Posted by **Monique** on Friday, November 4, 2011 at 2:41pm.

A glucose solution contains 55.8g of glucose (C6H12O6) in 455g of water. Calculate the freezing poing and boiling point of the solution. (Assume a density of 1.00 g/ml for water.

This what I did, I got moles of C6H12O6, 0.89 moles C6H12O6

then I got the mass of the solution 455g/1000kg, 0.455 I then divided 0.89 solute mol/0.455 kg solvent. I was going to do the formula for freezing and boiling but what do I do with the density. I hope I havent confused you. I guess I don't know what to do with the density or if I have set this up right.

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