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December 21, 2014

December 21, 2014

Posted by **brianna** on Friday, November 4, 2011 at 1:41pm.

I worked it out and came up with the answer 1421313.733.... i feel like this isnt right... please feel free to comment :)

- ***college algebra*** -
**Steve**, Saturday, November 5, 2011 at 4:00pmIf you mean g(x) = x^3/[2*(x-7)^(1/3)] then you are in trouble. The denominator of h(7) is zero.

So (goh)(7) is g(h(7)) is undefined.

If h(x) = x^3/2 * (x-7)^(1/3) then

h(7) = 0 and g(0) = 3.

How did you get your answer? Use parentheses to make it clear how to evaluate the functions.

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