Posted by brianna on Friday, November 4, 2011 at 1:41pm.
If you mean g(x) = x^3/[2*(x-7)^(1/3)] then you are in trouble. The denominator of h(7) is zero.
So (goh)(7) is g(h(7)) is undefined.
If h(x) = x^3/2 * (x-7)^(1/3) then
h(7) = 0 and g(0) = 3.
How did you get your answer? Use parentheses to make it clear how to evaluate the functions.
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