Posted by brianna on .
Let h(x) = x3/2(x  7)1/3 and g(x) = 200x3  47x2 + 9017x + 3. Utilize this information to find the value of (g o h)(7).
I worked it out and came up with the answer 1421313.733.... i feel like this isnt right... please feel free to comment :)

***college algebra*** 
Steve,
If you mean g(x) = x^3/[2*(x7)^(1/3)] then you are in trouble. The denominator of h(7) is zero.
So (goh)(7) is g(h(7)) is undefined.
If h(x) = x^3/2 * (x7)^(1/3) then
h(7) = 0 and g(0) = 3.
How did you get your answer? Use parentheses to make it clear how to evaluate the functions.