Posted by **mary** on Friday, November 4, 2011 at 8:28am.

m1 = 2.7 kg block slides on a frictionless horizontal surface and is connected on one side to a spring (k = 40 N/m) as shown in the figure above. The other side is connected to the block m2 = 3.6 kg that hangs vertically. The system starts from rest with the spring unextended.

a) What is the maximum extension of the spring?

- physics emergency -
**Damon**, Friday, November 4, 2011 at 4:40pm
total mass = 6.3 kg

mass falls a distance x and nothing is moving when it reaches maximum spring extension x

potential energy lost by mass going down = m g x = 3.6 g x

that is potential energy gained by spring (1/2) k x^2

so

(1/2) k x^2 = 3.6 g x

x = 7.2 g/k

- physics emergency -
**Anonymous**, Monday, November 21, 2011 at 4:27pm
how would you find the speed of the hanginf mass when the spring is extended 10cm?

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