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April 20, 2014

April 20, 2014

Posted by **Lynn** on Friday, November 4, 2011 at 2:39am.

The area of a rectangle = 105

The length is 2x+1

Width is x

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I tried solving it :

Arec = l x w

105 = (2x+1)x

105 = 2x^2 + x

0= 2x^2 + x - 105

This is where I get stuck on...

- Math -
**Damon**, Friday, November 4, 2011 at 5:53amquadratic equation

x = [ -1 +/- sqrt (1+840)]/4

= [ -1 +/- 29 ]/4

= 28/4 forget negative solution

= 7

or

(x - 7) (2x + 15) = 0

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