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October 2, 2014

October 2, 2014

Posted by **ninzyy** on Thursday, November 3, 2011 at 9:39pm.

top. Its ends are isosceles triangles with an

altitude of 2.1 ft and vertex down.

Water is being pumped into the trough at

a rate of 2.4 ft3/min.

How fast is the water level rising when the

water is 1.39 ft deep?

Answer in units of ft/min

(Sides of baseball diamond are all 90 ft)

For the baseball diamond shown in the figure

below, suppose the player is running from first

to second at a speed of 26 ft/s.

Find the rate at which the distance from

home plate is changing when the player is 38

ft from second base.

- Cal 1 -
**Steve**, Friday, November 4, 2011 at 12:29pmIf the water is x ft deep, its cross-section is a triangle with height x and width w. By similar triangles,

x/2.1 = w/2.6

w = 1.238x

The volume is 10*(1/2)*x*w = 5*x*1.238x = 6.19x^2

v = 6.19x^2

dv/dt = 12.38x dx/dt

2.43 = 12.38(1.39) dx/dt

dx/dt = 0.14 ft/min

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