posted by Millwe .
On a graph, the points (4,-2),(7,-2),(9,-5) and (2,-5) are connected in order to form a trapezoid. To the nearest tenth, what is its perimeter?
Compute the four side lenghts using the pairs of coordinates.
The side that goes from (4,-2) to (7,-2) has a length of sqrt[(7-4)^2 + (2 -(-2)^2] = 5
Do the others the same way.
Then add all four.
Thank you for your help, I still don't understand
In order to figure the length of a line segment, you have to rely on the Pythagorean Theorem. If that doesn't sound familiar, you need to review your text. The theorem states that in a right triangle with legs a and b, with hypotenuse c,
c2 = a2 + b2
Now, if you plot two points on a piece of graph paper, such as (7,-2) and (9,-5), the line joining the points will be a slanting line. If you draw horizontal and vertical lines from each point, they will intersect to form a right triangle. The length of the legs are just the x-distance from 7 to 9 = 2, and the y-distance from -5 to -2 = 3.
So, the length of the hypotenuse is given by
h2 = 22 + 32
h2 = 13
h = √13
If you follow these steps for each side of the figure, you can add up all the lengths to get the perimeter.