Write a formula for the compound that forms from potassium and acetate.
what is the molarity of an NaOH solution if 28.2 ml of a o.355 M H2SO4 solution is required to neutralize a 250 mL sample of the NaOH solution?
Potassium ion is K^+
Acetate ion is C2H3O2^-
Potassium acetate is KC2H3O2.
Pearl. You will do better not to piggy back onto another post with your own. You take the risk that we will think your question is the answer to the post and never read either. Go to the top of the page and click on Post a new question.
Look at the H3PO4 problem. Your H2SO4 is worked the same way except the equation is slightly different.
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
To determine the formula for the compound that forms from potassium and acetate, we first need to understand the valency or charge of each element.
Potassium (K) is an alkali metal with a valency of +1. This means that it tends to lose one electron to achieve a stable electron configuration.
Acetate is the ion formed by the deprotonation of acetic acid. The formula for acetate is CH3COO-, where there is a negative charge on the ion.
Considering the valency of potassium and the charge of acetate, we can determine the formula by a simple crisscross method:
The crisscross method involves taking the absolute values of the charges on each ion and then placing them as subscripts on the opposite ion.
In this case, we have:
(+1) potassium (K) and (-1) acetate (CH3COO-).
The crisscrossing gives us:
K1CH3COO1,
which can be simplified to:
KCH3COO.
Therefore, the formula for the compound formed from potassium and acetate is KCH3COO.