Post a New Question

Calculus

posted by on .

A 20' ladder leans against a building. The bottom of the ladder is sliding away horizontally at a rate of 2 feet per second. How fast is the top of the ladder sliding down the building when it is 12' above the ground?

  • Calculus - ,

    If you draw a diagram, let x be the distance of the base of the ladder from the wall, and h the height of the ladder against the wall:

    x^2 + h^2 = 400

    When h = 12,
    x^2 = 400 - 144 = 256
    x = 16


    2x dx/dt + 2h dh/dt = 0
    32 * 2 + 24 dh/dt = 0
    dh/dt = -64/24 = -8/3

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question