Posted by Mandy on Wednesday, November 2, 2011 at 9:05pm.
In a city with no cars of mixed color, 30% of the cars on the road are brown. Forty percent are either brown or green, and 10% are white.
a.) What is the probability that a randomly selected car is green?
b.) What is the probability that a randomly selected car is not brown, green, or white?
Thanks a bunch for whoever can help!?
- Statistics - Mariella., Wednesday, November 2, 2011 at 9:09pm
How many cars were there altogether?
- Statistics - Mandy, Wednesday, November 2, 2011 at 9:13pm
It doesn't say how many cars in total there were. Im guessing that in total these cars added up to 100%.
- Statistics - Mariella., Wednesday, November 2, 2011 at 9:16pm
- Statistics - Mandy, Wednesday, November 2, 2011 at 9:19pm
Is there anyway that you can show me how you got that so I can understand a little better? Thanks!
- Statistics - Mariella., Wednesday, November 2, 2011 at 9:22pm
a.)40% of cars are either brown or green. Divide that by two since there are two colors. You get 20. Put that over 100=20/100. Reduce it to 2/10 which reduces to 1/5.
b.)Add all the percents together to get 80%. Subtract it from 100. 100-80=20. 20/100=1/5. So the actual answer to b is 1/5. Sorry, my mistake. :P
- Statistics - Mandy, Wednesday, November 2, 2011 at 9:25pm
Thanks a bunch!
- Statistics - Mariella., Wednesday, November 2, 2011 at 9:26pm
- Statistics - PsyDAG, Wednesday, November 2, 2011 at 10:22pm
What about the undefined remaining 20%?
30% + 40% + 10% = only 80%
- Statistics - Jade, Thursday, November 3, 2011 at 7:38pm
She DID do that.
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