Posted by **Mandy** on Wednesday, November 2, 2011 at 9:05pm.

In a city with no cars of mixed color, 30% of the cars on the road are brown. Forty percent are either brown or green, and 10% are white.

a.) What is the probability that a randomly selected car is green?

b.) What is the probability that a randomly selected car is not brown, green, or white?

Thanks a bunch for whoever can help!?

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**Mariella.**, Wednesday, November 2, 2011 at 9:09pm
How many cars were there altogether?

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**Mandy**, Wednesday, November 2, 2011 at 9:13pm
It doesn't say how many cars in total there were. Im guessing that in total these cars added up to 100%.

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**Mariella.**, Wednesday, November 2, 2011 at 9:16pm
a.)1/5

b.)1/4

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**Mandy**, Wednesday, November 2, 2011 at 9:19pm
Is there anyway that you can show me how you got that so I can understand a little better? Thanks!

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**Mariella.**, Wednesday, November 2, 2011 at 9:22pm
a.)40% of cars are either brown or green. Divide that by two since there are two colors. You get 20. Put that over 100=20/100. Reduce it to 2/10 which reduces to 1/5.

b.)Add all the percents together to get 80%. Subtract it from 100. 100-80=20. 20/100=1/5. So the actual answer to b is 1/5. Sorry, my mistake. :P

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**Mandy**, Wednesday, November 2, 2011 at 9:25pm
Thanks a bunch!

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**Mariella.**, Wednesday, November 2, 2011 at 9:26pm
No problem.(:

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**PsyDAG**, Wednesday, November 2, 2011 at 10:22pm
What about the undefined remaining 20%?

30% + 40% + 10% = only 80%

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**Jade**, Thursday, November 3, 2011 at 7:38pm
She DID do that.

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