Posted by **Susie** on Wednesday, November 2, 2011 at 7:35pm.

A sample of limonene has a specific rotation of +81.5. (Given that R-(+)-limonene = +125.5 and, S-(-)-limonene = -122.1).

What is the %ee?

______%ee

What is the molecular composition of this same sample?

S isomer = ______%

R isomer = ______%

This is how I solved for the R and S isomer:

Let x = % of R

Let 100-x = % of S

125.6x + [(-122.1)(100-x)/100] = 81.5

125.6x - 12210 + 122.1x = 8150

247.7x = 20360

x = 82% = R isomer

100-82 = 18% = S isomer

That's how I solved for the % of R and S isomer. I'm not even sure if I solved correctly.

And for the %ee, I have no idea how to do it! I know that you divide measured specific rotation of mixture by specific rotation of pure enantiomer and then multiply by 100, but in this case, the the values for the R and S are different, so I'm not sure where to go from there.

Please help!

## Answer this Question

## Related Questions

- ochem - A sample of Limonene has a specific rotation of +76.9. What is the % ee ...
- ochem - A sample of Limonene has a specific rotation of +76.9. What is the % ee ...
- OChem - If the limonene reactant described in question 2 is composed of a single...
- Chemistry - A pure sample of (R)-limonene has a specific rotation of +125.6. If ...
- Chem - I have another question concerning (S) & (R) enantiomers of Limonene. How...
- chemistry - Bromine can be added to limonene to created a brominated compound. ...
- Chemistry - Bromine can be added to limonene to create a brominated compound. ...
- Ochem - If you start with 2.97 g of zest and obtain 459 mg of pure limonene, ...
- chemistry - 2. Bromine can be added to limonene to create a brominated compound...
- Organic chemi - I have a calculated enantiomeric excess value of 7% for my ...