Posted by Jackie on Wednesday, November 2, 2011 at 1:51pm.
First, let's solve the equation for y to determine the slope of the line.
-6x + 8y = 3
8y = 6x + 3
y = (6/8)x + 3/8 = (3/4)x + 3/8
Slope = 3/4
The slope of a line perpendicular to this one must be its negative reciprocal, or -4/3.
Now, use the point-slope form to find the other line:
y - y1 = m(x - x1)
y - (-15) = -4/3 [x - (-3)]
y + 15 = -4/3 (x + 3)
y + 15 = (-4/3)x - 4
y = (-4/3)x - 4 - 15
y = (-4/3)x - 19
And there you have it! By showing you the steps, I hope this will help with other problems of this type.
Related Questions
Algebra II - Can you make sure my Algebra II work is correct? I've done the ...
math - A line passes through the origin and the point (-6, 4). Write the ...
math - i have more than one question so if u no any of the answers please tell ...
Algebra2 - Write an equation for the line in point/slope form and slope/...
algebra[please check] - in questions 1 and 2, write an equation of the line in ...
algebra (check plz) - write an equation in slope-intercept form of the line that...
pre calculus - write the slope-intercept form of an equation for a line that ...
Algebra - Can someone check my answers? 1. Write the equation of the line that ...
algebra - Write the slope-intercept equation for the line that passes through (-...
mat 101 - Equation for a line that passes through (6,26) and has a slope of 3 ...
For Further Reading
