Posted by Jackie on Wednesday, November 2, 2011 at 1:51pm.
Write the slopeintercept equation for the line that passes through (3,15)and is perpendicular to 6x+8y=3

Algebra  MathGuru, Thursday, November 3, 2011 at 1:04pm
First, let's solve the equation for y to determine the slope of the line.
6x + 8y = 3
8y = 6x + 3
y = (6/8)x + 3/8 = (3/4)x + 3/8
Slope = 3/4
The slope of a line perpendicular to this one must be its negative reciprocal, or 4/3.
Now, use the pointslope form to find the other line:
y  y1 = m(x  x1)
y  (15) = 4/3 [x  (3)]
y + 15 = 4/3 (x + 3)
y + 15 = (4/3)x  4
y = (4/3)x  4  15
y = (4/3)x  19
And there you have it! By showing you the steps, I hope this will help with other problems of this type.
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