Homework Help: Physics

Posted by dan on Wednesday, November 2, 2011 at 12:03pm.

A 72.0 kg skateboarder wants to just make it to the upper edge of a "quarter pipe", a track that is one-quarter of a circle with a radius of 4.65 m. What speed (in m/s) does he need at the bottom assuming that the local acceleration due to gravity is 9.80 m/s2?

Physics - drwls, Wednesday, November 2, 2011 at 12:27pm
The KE at the bottom (where the velocity is a maximum value V, must equal the PE increase at the top, where the velocity is 0. .

(1/2)MV^2 = M g R

V = sqrt (2 g R) = 9.55 m/s

Answer this Question

Related Questions

Physics - A 72.0 kg skateboarder wants to just make it to the upper edge of a &...
Physics - A 61 kg skateboarder wants to just make it to the upper edge of a &...
Physics helppp - A 67.0 kg skateboarder wants to just make it to the upper edge ...
physics - A 4.74 kg spherical ball with radius 1.4 cm rolls on a track with a ...
Physics - The drawing shows a skateboarder moving at v = 5 m/s along a ...
physics - A 4.74 kg spherical ball with radius 1.4 cm rolls on a track with a ...
physics - You are on a train that is traveling at 3.0 m/s along a level straight...
Physics - You are on a train that is traveling at 3.0 m/s along a level straight...
Intergrated physics and chemistry - A 52.0-kilogram skateboarder does a trick on...
physics - Water is flowing in a pipe as depicted in the figure. As shown, p = ...

For Further Reading

First Name:
School Subject:
Answer: