A 250-ohm resistor is connected in parallel with a 190-ohm resistor. What is their equivalent resistance?

1/Rt=1/250+1/190 Off hand, I am guessing 110 ohms

doing the algebra,
Rt=(250*190)/(250+190)=108ohms

To find the equivalent resistance of resistors connected in parallel, use the following formula:

1/Req = 1/R1 + 1/R2 + ...

Given:
R1 = 250 ohms
R2 = 190 ohms

1/Req = 1/250 + 1/190

To simplify the calculation, find the least common multiple (LCM) of 250 and 190, which is 4750.

1/Req = (190 + 250) / (250 * 190)
= 440 / 47500

Now, take the reciprocal of both sides:

Req = 47500 / 440
= 107.95454545 ohms

Therefore, the equivalent resistance of the 250-ohm resistor and the 190-ohm resistor connected in parallel is approximately 107.95 ohms.

To find the equivalent resistance, we need to use the formula for resistors connected in parallel.

The formula for the equivalent resistance (R_eq) of two resistors (R1 and R2) connected in parallel is:

1/R_eq = 1/R1 + 1/R2

Let's plug in the values given in the problem:

1/R_eq = 1/250 + 1/190

To simplify the calculation, we can find a common denominator for 250 and 190, which is 4750.

So the equation becomes:

1/R_eq = (19/4750) + (25/4750)

Now, let's add the fractions:

1/R_eq = (19 + 25)/4750

1/R_eq = 44/4750

To calculate R_eq, we take the reciprocal of 44/4750:

R_eq = 4750/44

Simplifying the fraction gives:

R_eq = 107.9545 ohms (rounded to four decimal places)

Therefore, the equivalent resistance of a 250-ohm resistor and a 190-ohm resistor connected in parallel is approximately 107.9545 ohms.