Posted by Web7 on Wednesday, November 2, 2011 at 3:30am.
If the boat is x meters from the dock, then the length of rope is given by
r^2 = x^2 + 1
2r r' = 2x x' = 2(8)(-1)
rr' = -8
So, r(8) = √65
r'√65 = -8
r' = 0.992 m/s
Makes sense; since the boat is far away as compared to the height, the rope length is essentially the distance away, so dr/dt is about the same as dx/dt.
The closer the boat gets, the slower the rope length decreases; when the boat is very near the dock, the rope length essentially stays at 1 meter.
I like apples
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