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October 23, 2014

October 23, 2014

Posted by **Web7** on Wednesday, November 2, 2011 at 3:30am.

b)A particle is moving along the curve y=√x. As the particle passes through the point (4,2), its x-coordinate increases at a rate of 3cm/s. How fast is the distance from the particle to the origin changing at this instant?

c)The price (in dollars) p and the quantity demanded q are related by the equation: p2+2q2=1100.

If R is revenue, dR/dt can be expressed by the following equation: dR/dt=A(dp/dt),

where A is a function of just q.

i)Find A.

ii)Find dR/dt when q=20 and dp/dt=4.

- Calculus -
**Steve**, Wednesday, November 2, 2011 at 11:58amIf the boat is x meters from the dock, then the length of rope is given by

r^2 = x^2 + 1

2r r' = 2x x' = 2(8)(-1)

rr' = -8

So, r(8) = √65

r'√65 = -8

r' = 0.992 m/s

Makes sense; since the boat is far away as compared to the height, the rope length is essentially the distance away, so dr/dt is about the same as dx/dt.

The closer the boat gets, the slower the rope length decreases; when the boat is very near the dock, the rope length essentially stays at 1 meter.

- Calculus -
**Anonymous**, Tuesday, October 30, 2012 at 1:46amI like apples

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