Posted by **Keelia** on Wednesday, November 2, 2011 at 12:20am.

You push a 4.6 kg block against a horizontal spring, compressing the spring by 27 cm. Then you release the block, and the spring sends it sliding across a tabletop. It stops 63 cm from where you released it. The spring constant is 250 N/m. What is the coefficient of kinetic friction between the block and the table?

- physics -
**drwls**, Wednesday, November 2, 2011 at 12:45am
Get the initial velocity Vo using conservation of energy.

(1/2)MVo^2 = (1/2)kX^2

(X = 0.27 m is the spring compression; k is the spring constant)

After you have Vo, use KE = work done to stop.

(1/2) M Vo^2 = Uk*M*g

Actually you can skip the Vo step and just use

(1/2)*k*X^2 = Uk*M*g

Solve for Uk, the kinetic friction coefficient

## Answer This Question

## Related Questions

- Physics - You push a 2.5 kg block against a horizontal spring, compressing the ...
- physics - You push a 1.9 kg block against a horizontal spring, compressing the ...
- physics - You push a 2.0 kg block against a horizontal spring, compressing the ...
- physics - You push a 1.3 kg block against a horizontal spring, compressing the ...
- Physics - You push a block of mass m against a horizontal spring, compressing ...
- physics - 2. You push a 2.0 Kg block against a horizontal spring (the spring ...
- Physics - A 540 g block is released from rest at height h0 above a vertical ...
- Physics - A 540 g block is released from rest at height h0 above a vertical ...
- Physics please help????? - A 540 g block is released from rest at height h0 ...
- Physics - A 2.5-kg block is sliding along a rough horizontal surface and ...

More Related Questions