Posted by Shawn on Tuesday, November 1, 2011 at 10:40pm.
Given f(x)=sin(x)2cos(x) on the interval [0,2pi].
a) Determine where the function is increasing and decreasing.
b) Determine where the function is concave up and concave down.
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I know:
f′(x)=cos(x)+2sin(x)
f″(x)=sin(x)+2cos(x)
Other than that^^ I have no clue how to get the intervals where the function is increasing/decreasing and where it's concave up/concave down.

calculus  Steve, Wednesday, November 2, 2011 at 11:15am
Go back and review he subject.
The function is increasing where f' > 0
The curve is concave up where f'' > 0.
Now just check 'em out.