Posted by **Shawn** on Tuesday, November 1, 2011 at 10:40pm.

Given f(x)=sin(x)-2cos(x) on the interval [0,2pi].

a) Determine where the function is increasing and decreasing.

b) Determine where the function is concave up and concave down.

________________________________________

I know:

f′(x)=cos(x)+2sin(x)

f″(x)=-sin(x)+2cos(x)

Other than that^^ I have no clue how to get the intervals where the function is increasing/decreasing and where it's concave up/concave down.

## Answer this Question

## Related Questions

- Calculus - Given f(x)=sin(x)-2cos(x) on the interval [0,2pi]. Determine where ...
- Calculus - Given f(x)=sin(x)-2cos(x) on the interval [0,2pi]. Determine where ...
- APCalculus - For the function y=2sin(x)-cos^2(x) on [0, 2pi] find the following...
- Calculus - Consider the function f(x)=xlnx. For the following questions, write ...
- Calculus - Let f be the function defined for x >or= to 0 with f(0)=5 and f', ...
- Calculus - Consider the function f(x)=3cosx−cos^(3)x for 0<x<2π...
- Calculus (Urgent Help) - Okay, I need major help! Can someone tell me if these ...
- calculus - Consider the exponential function . Which of the following best ...
- Please check my Calculus - 1. Given f(x)=-6/x, choose the correct statement A. ...
- Calculus(urgent please help) - Consider the following function f(x)=x^2/[x^2-9] ...

More Related Questions