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Posted by on Tuesday, November 1, 2011 at 10:40pm.

Given f(x)=sin(x)-2cos(x) on the interval [0,2pi].

a) Determine where the function is increasing and decreasing.
b) Determine where the function is concave up and concave down.
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I know:

f′(x)=cos(x)+2sin(x)
f″(x)=-sin(x)+2cos(x)

Other than that^^ I have no clue how to get the intervals where the function is increasing/decreasing and where it's concave up/concave down.

  • calculus - , Wednesday, November 2, 2011 at 11:15am

    Go back and review he subject.

    The function is increasing where f' > 0
    The curve is concave up where f'' > 0.

    Now just check 'em out.

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