Homework Help: Bepper

Posted by Sarah on Tuesday, November 1, 2011 at 10:27pm.

One end of a long 26 foot ladder is on the floor and the other end rests on a verical wall the bottom end of the ladder is pulled away from the wall qt a rate of 4 feet per second. how fast is the angle formed by the ladder and the floor changing when the ladder is 10 feet away from the wall

calculus - related rates? - drwls, Wednesday, November 2, 2011 at 12:06am
"bepper" is not a subject I am familiar with.

Let x be the distance of the bottom from the wall.

x = (26 ft)*sin(theta)

dx/dt = 26 cos(theta)* d(theta)/dt = 4 ft/s
Solve for d(theta)/dt. It will be in radians per second.

Answer this Question

Related Questions

physics - A straight ladder is leaning against the wall of a house. The ladder ...
Physics - a 76 kg window cleaner uses a 12 kg ladder that is 5.8 m long. he ...
math - A uniform ladder of length 2a and mass m lies on a vertical plane with ...
physics - A straight ladder is leaning against the wall of a house. The ladder ...
physics - In Figure 12-6, a ladder of length L = 12 m and mass m = 46 kg leans ...
math - A ladder , 5 meter long , standing on a horizontal floor , leans against ...
Calculus - a 5m ladder rests against a vertical wall. The top of the ladder ...
Maths - A ladder, 6m long rests against a wall. The foot of the ladder is 2.5m ...
physics - A straight ladder is leaning against the wall of a house. The ladder ...
Physics Mehanics - A meter stick is held vertically with one end on the floor ...

For Further Reading

First Name:
School Subject:
Answer: