Posted by Emily on Tuesday, November 1, 2011 at 10:10pm.
area=1/2 y x
but y=above, so
area=1/2 x^5(e^-7x)
darea/dx=5/2 x^4(e^-7x)-7/2 x^5(e^-7x)=0
divide by x^4 e^-7x
0=5/2 -7/2x
x=5/7
y=you do it, then solve for Area.
check my work.
Related Questions
calculus - The hypotenuse of a right triangle has one end at the origin and one ...
math/calc - The hypotenuse of a right triangle has one end at the origin and one...
math/calc - The hypotenuse of a right triangle has one end at the origin and one...
Calculus - The hypotenuse of a right triangle has one end at the origin and one ...
Math - If the hypotenuse of a right triangle is 13 and one of its legs is 5, ...
Repost- Calculus; someone please help - Please help out. Thank you. A right ...
Calculus - A right triangle has one leg on the x-axis. The vertex at the right ...
Geometry - Which is the hypotenuse-leg theorem? A. If the hypotenuse and one leg...
geometry - The hypotenuse of a right triangle is 8cm and one leg is 6cm. Find ...
Calculus - A circle C has center at the origin and radius 9. Another circle K ...
For Further Reading