Posted by John on Tuesday, November 1, 2011 at 8:36pm.
You jog at 6.2 mi/h for 5.0 mi, then you jump into a car and drive for another 5.0 mi. With what average speed must you drive if your average speed for the entire 10.0 miles is to be 10.6 mi/h?
I don't get why the answer isn't 15.

physics  tchrwill, Tuesday, November 1, 2011 at 9:33pm
The average speed for the entire trip is the total distance divided by the total time.
Therefore,
t1 = 5/6.2 = .806 hr.
t2 = 5/V
Total distance traveled is 5 + 5 = 10 miles.
Total time is t1 + t2 = .806 + 5/V
Average driving speed is therefore
Vavg = 10/(.806 + 5/V) = 10.6
Solving,V = 36.511mph.
(5 + 5)/(.806 + 5/36.511) = 10.6mph.
Answer This Question
Related Questions
 physics  You jog at 6.0 mi/h for 5.0 mi, then you jump into a car and drive for...
 physics  You jog at 6.0 mi/h for 5.0 mi, then you jump into a car and drive for...
 physics  You jog at 6.0 mi/h for 5.0 mi, then you jump into a car and drive for...
 math  You jog at 6.6 mi/h for 5.0 mi, then you jump into a car and drive for ...
 physics  You jog at 9.5 km/h for 7.0km , then you jump into a car and drive an ...
 Physics  To get to a concert on time, Dakota has to drive 122 miles in 2.00 hrs...
 Science  Physics  How long would it take you to drive from Houston to ...
 Physic Help  In heavy rushhour traffic in Atlanta, you drive in a straight ...
 physics 101  You drive your car at a speed 40km/h for 1 hour, then slow down to...
 math (pre calc)  Imagine that you are driving 150 miles and you want your ...
More Related Questions