Posted by **John** on Tuesday, November 1, 2011 at 8:36pm.

You jog at 6.2 mi/h for 5.0 mi, then you jump into a car and drive for another 5.0 mi. With what average speed must you drive if your average speed for the entire 10.0 miles is to be 10.6 mi/h?

I don't get why the answer isn't 15.

- physics -
**tchrwill**, Tuesday, November 1, 2011 at 9:33pm
The average speed for the entire trip is the total distance divided by the total time.

Therefore,

t1 = 5/6.2 = .806 hr.

t2 = 5/V

Total distance traveled is 5 + 5 = 10 miles.

Total time is t1 + t2 = .806 + 5/V

Average driving speed is therefore

Vavg = 10/(.806 + 5/V) = 10.6

Solving,V = 36.511mph.

(5 + 5)/(.806 + 5/36.511) = 10.6mph.

## Answer this Question

## Related Questions

- physics - You jog at 6.0 mi/h for 5.0 mi, then you jump into a car and drive for...
- physics - You jog at 6.0 mi/h for 5.0 mi, then you jump into a car and drive for...
- physics - You jog at 6.0 mi/h for 5.0 mi, then you jump into a car and drive for...
- math - You jog at 6.6 mi/h for 5.0 mi, then you jump into a car and drive for ...
- physics - You jog at 9.5 km/h for 7.0km , then you jump into a car and drive an...
- Physics - To get to a concert on time, Dakota has to drive 122 miles in 2.00 hrs...
- Math - A woman went for a 48km drive in her car, partly in town in the country. ...
- Pre calculus - A woman went for a 48km drive in her car, partly in town in the ...
- Physics - You drive your car from home at an average spped of 78km/h for 2 h. ...
- Physics - A jogger runs eastward in a straight line with an average speed of 2....

More Related Questions