Posted by Bobbie on Tuesday, November 1, 2011 at 8:00pm.
A force of 9000 N is used to stop a 1500kg car traveling at 20 m/s. What braking distance is needed to bring the car to a halt?

physics  Henry, Thursday, November 3, 2011 at 10:51pm
a = F / m = 9000 / 1500 = 6m/s^2.
d = (Vf^2  Vo^2) / 2a,
d = (0  (20)^2) / 12 = 33.33m. 
physics  Demiurge, Wednesday, May 20, 2015 at 7:52am
Kinetic energy of car before breaking:
Wk = mass * velocity^2/2
Wk = 1500 * 20^2/2
The work done by the car to transfer kinetic energy to frictional heat:
W(friction) = Force * Distance
9000n * Distance
As no energy can be lost only transformed, we can write: 1500 * 20^2 /2 = 9000n * distance
solving for distance we get:
Distance = 1500 * 20^2/2 * 9000
Distance = 33,333
As distance can't be negative and is a scalar quantity we can write 33.333m