In the cchemistry lab we conducted an experiment called atomic spectroscopy.

We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury.

For hydrogen:
red 1.90ev 650nm 1.54e^-3
red 2.02ev 610nm 1.64e^-3
green 2.30ev 545nm 1.83e^-3

for neon:
green 2.30ev 550nm 1.82e^-3
red 2.05ev 610nm 1.64e^-3
red 1.80ev 690 1.45e^-3
yellow 2.12 580 1.72e^-3
blue 2.65 470 2.13e^-3

for mercury:
green 2.30ev 548 1.823^-3
red 2.05 590 1.69e^-3
violet 2.85 440 2.27e^-3
blue 2.55 470 2.13e^-3
yellow 2.15 570 1.75e^-3

for the first question we had to derive the equation that would allow us to find Planck's constant from your graph using the formulas
c= lamda X v and E=hv

The teacher said that the equation is h=slope / c

The next question says to show the calculations of Planck's constant, including the unit conversions, for mercury, neon, and hydrogen using the equation created above.

I am not sure how to do this. I do not know where to start.

We had to create graphs for neon and hydrogen on the computer so would i use the slope from there?

on the x axis was 1/wavelength (nm-1) and the y axis was energy(ev). The line for both graphs of neon and hydrogen was positive. So would I pick two points on the graph to find the slope and then do h=slope/c?

let w = wavelength (I can't type the symbol).

E = hc/w; So the slope is E/(1/w) = E*w.
You can see that E*w = slope = hc so slope/c = h.
Yes, pick a couple of points on the y axis and determine the slope.

In the cchemistry lab we conducted an experiment called atomic spectroscopy.

We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury.

For hydrogen:
red 1.90ev 650nm 1.54e^-3
red 2.02ev 610nm 1.64e^-3
green 2.30ev 545nm 1.83e^-3

for neon:
green 2.30ev 550nm 1.82e^-3
red 2.05ev 610nm 1.64e^-3
red 1.80ev 690 1.45e^-3
yellow 2.12 580 1.72e^-3
blue 2.65 470 2.13e^-3

for mercury:
green 2.30ev 548 1.823^-3
red 2.05 590 1.69e^-3
violet 2.85 440 2.27e^-3
blue 2.55 470 2.13e^-3
yellow 2.15 570 1.75e^-3

for the first question we had to derive the equation that would allow us to find Planck's constant from your graph using the formulas
c= lamda X v and E=hv

The teacher said that the equation is h=slope / c

The next question says to show the calculations of Planck's constant, including the unit conversions, for mercury, neon, and hydrogen using the equation created above.

I am not sure how to do this. I do not know where to start.

We had to create graphs for neon and hydrogen on the computer so would i use the slope from there?

on the x axis was 1/wavelength (nm-1) and the y axis was energy(ev). The line for both graphs of neon and hydrogen was positive. So would I pick two points on the graph to find the slope and then do h=slope/c?



Chemistry - DrBob222, Tuesday, November 1, 2011 at 7:50pm
let w = wavelength (I can't type the symbol).
E = hc/w; So the slope is E/(1/w) = E*w.
You can see that E*w = slope = hc so slope/c = h.
Yes, pick a couple of points on the y axis and determine the slope.

to calculate the slope i picked points (2.85, 0.00227) and (2.05, 0.00169). So i did 2.85-2.05 / .00227 -.00169 and ended up with .80/.00058. Is this correct.

To calculate Planck's constant using the equation h = slope / c, you need to find the value of the slope from the graphs you created for neon and hydrogen. Here's how you can do it step by step:

1. Start with the equation E = hv, which relates the energy (E) of a photon to its frequency (v) using Planck's constant (h).

2. Rearrange the equation to solve for frequency: v = E / h.

3. Recall that the speed of light (c) is given by the equation c = λv, where λ is the wavelength. Rearrange this equation to solve for frequency: v = c / λ.

4. Set the expressions for frequency equal to each other, since they both represent the same quantity: E / h = c / λ.

5. Rearrange the equation to make h the subject: h = Eλ / c.

6. Notice that the equation h = slope / c given by your teacher is consistent with this rearrangement, where slope represents the ratio Eλ.

7. Now, let's apply this equation to calculate the values of Planck's constant for mercury, neon, and hydrogen. You will need to use the given values of energy (E), wavelength (λ), and the speed of light (c).

8. For example, let's consider hydrogen. From the given data, you have three pairs of values: (1.90 eV, 650 nm), (2.02 eV, 610 nm), and (2.30 eV, 545 nm).

9. Convert the wavelength from nanometers to meters by dividing by 10^9, since the unit of speed of light is meters per second.

10. Convert the energy from electron-volts (eV) to joules (J) by multiplying by the conversion factor 1.602 x 10^(-19) J/eV. This is because 1 eV is equivalent to 1.602 x 10^(-19) J.

11. Calculate the value of Eλ by multiplying the energy (in joules) by the wavelength (in meters).

12. Choose two points on the graph where the line is positive, and calculate the slope (Δy / Δx) by using the formula (y2 - y1) / (x2 - x1). Here, the y-axis represents Eλ and the x-axis represents 1/λ.

13. Once you have the slope, substitute it into the equation h = slope / c, and divide by the value of c (speed of light).

Repeat this process for neon and mercury using the respective data provided.

Remember to use proper units throughout the calculations.