# College algebra

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system of linear equation

The sum of 3 numbers is 14
the largest is 4 times the smallest
the sum of the smallest and twice the largest is 18
what are the 3 numbers? show work?

A. how many unknowns you have?
-how many equations need to be solve for that many unknown?

B. what are the equations?

C. used the system of equations using matrices.

• College algebra -

x+y+z=14
z=4x
x+2z=18
=================
x+y+4x = 14 or 5x+y = 14
x+8x = 18
or x = 2
so
y = 14 - 10 = 4
z = 4*2=8
3 unknowns, three equations
I did it with substitution, however can form augmented matrix and use Gauss Jordan:
+1 1 1 14
-4 0 1 0
+1 0 2 18

then plug and chug

• College algebra -

post it.

• College algebra -

matix solution
|1 1 1 | [x y z]'= [14 0 18]'
|4 0 1 |
|1 0 2 |

H*[x y z]' = [14 0 18]' (' stands for transpose; in this case makes row vector a column vector)

inv(H)*H*[x y z]'= inv(H)*[14 0 18]'

[x y z] = inv(H)*[14 0 18]'

inverting a 3x3 matrix

|+(0-0) -(-8-1) +(0-0)|'
|-(2-0) -(2-1) -(0-1)|
|+(1-0) -(1+4) +(0+4)|

|0 9 0|'
|-2 -1 1|
|1 -5 4|

=|0 -2 1|
|9 -1 -5|
|0 1 4|

det(H)= use the second column
since it has 2 zeros it makes
it easy.

det(H)=-1(-8-1)+0*(2-1)-0*(1+4)=9

inv(H)=1/9*|0 -2 1|
|9 -1 -5|
|0 1 4|

[x y z]'= inv(H)*[14 0 18]'

=[18/9 (9*14-5*18)/9 (18*4)/9]'
=[ 2 4 8 ]'

hope this helps