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January 30, 2015

January 30, 2015

Posted by **Haley** on Tuesday, November 1, 2011 at 4:59pm.

- Calc-please help! -
**Steve**, Wednesday, November 2, 2011 at 12:06amJust do a web search for online graphing calculators. There are bunches.

y = x^{3}/(x^{2}-1)

y' = [3x^{2}* (x^{2}-1) - x^{3}* 2x]/(x^{2}-1)^{2}

= (x^{4}- 3x^{2})/(x^{2}-1)^{2}

y'' = [(4x^{3}- 6x)(x^2-1)^{2}- (x^{4}- 3x^{2})*2*(x^{2}-1)*2x]/(x^{2}-1)^{4}

= (2x^{3}+ 6x)/(x^{2}-1)^{3}

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