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Posted by on Tuesday, November 1, 2011 at 3:02pm.

The following four forces act on 4.00 kg object:
F1 = 300 N east
F2 = 700 N north
F3 = 500 N west
F4 = 600 N south
What is the acceleration of the object?

  • Physics! - , Tuesday, November 1, 2011 at 3:03pm

    resultant N: 100N
    reslultantW: 200W

    resulatant: sqrt50000 in the direction arctan 2 N of W

    acceleration=that force/4kg

  • Physics! - , Wednesday, December 30, 2015 at 7:38am

    F3-F1
    500-300
    200N west

    F2-F4
    700-600
    100N north


    100N north and 200N west
    100^2+200^2=c^2
    10000+40000=c^2
    50000=c^2
    √50000=c
    100√5=c
    223.6N

    tanx=200/100
    tanx=2
    x=arctan(2)
    x=63.4 degrees

    223.6N, 63.4 degrees west of north.

    f=ma
    223.6/4=a
    55.9m/s^2=a

    55.9m/s^2 63.4 degrees west of north.

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