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December 20, 2014

December 20, 2014

Posted by **Mishaka** on Tuesday, November 1, 2011 at 2:37pm.

g(x) = -500/x, x cannot equal 0.

I know that in order to fnd the derivative I need to put the function into the equation for evaluating derivatives as limits.

lim as h -> 0 (f(x+h) - f(x))/h

I did this, but I am having difficulties simplifying it to evaluate the limit. Any help at all is appreciated!

- Calculus (Derivatives) -
**bobpursley**, Tuesday, November 1, 2011 at 2:54pmLet K= -500

lim (K/(x+h) - K/x)/h

lim K (x-x-h)/x(x+h)h

= -K (h/x(x+h)h=lim -K 1/x(x+h)

= -k/x^2

= 500/x^2

- Calculus (Derivatives) -
**Mishaka**, Tuesday, November 1, 2011 at 4:48pmOkay. So, 500/x^2 would be the simplified equation for the derivative, and from here I can figure that the limit is 5,000,000 as h approaches 0. Is this correct?

- Calculus (Derivatives) -
**Rodney**, Tuesday, November 1, 2011 at 11:20pmI too was able to come to the derivative of 500/x^2

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