Posted by Alexis on Tuesday, November 1, 2011 at 7:12am.
(a) If f(t) = Pe^(rt)
200 = P^0 = P (Therefore P = 200)
2000 = 200 e^(3r)
e^3r = 10
3r = ln10 = 2.303
r = 0.76753
The equation is
f(t) = 200*e^(0.76753 t)
(b) 2000 = 200*a^3
a^3 = 10
a = 2.15443
y = 200*(2.15443)^x
(c) Solve 5000 = 200*2.15443^x
25 = 2.15443^x
x = ln25/ln2.15443 = 4.1938
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