Posted by Nabil on Tuesday, November 1, 2011 at 7:07am.
a)
L = 60/(3+17e^-0.1t)
Substitute t=0, remember that any number to the power 0=1
b)
L = 60/(3+17e^-0.1t)
substitute L=10
10=60/(3+17e^-0.1t)
3+17e^-0.1t=6
17e^-0.1t = 3
e^-0.1t=3/17
ln(e^-0.1t)=ln(3/17)
-0.1t=ln(3/17)=-1.7346
0.1t=1.7346
t=17.346 hours
But check the maths!
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