Thursday
April 17, 2014

Homework Help: Math- integration

Posted by Candice on Tuesday, November 1, 2011 at 4:24am.

Find the area bounded by x^(2/3) and x= y^2 in the first quadrant.

(I've worked out the x intercepts to be 0 and 1 in the first quadrant, but how would I find the area?)

thanks :)

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

calculus - 1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x...
Calc - finding area bounded by curve - Find the area bounded by x=cubed root of ...
maths - use an iterated integral to find area of region bounded by graphs sin(x...
calculus - 10). Find the area of the region bounded by the graph of f(x)=4lnx/x...
Calculus - Find the area of the region bounded by the line y=3x and y= x^3 + 2x^...
calculus help lttle question - find the area of the regin bounded by the graphs ...
calculus - The figure shows the region bounded by the x-axis and the graph of . ...
integration - sqrt2 times e^t times t^(1/2) dt bounded between 0 and 1. i tried ...
Calculus - Let f be the function given by f(x)=(x^3)/4 - (x^2)/3 - x/2 + 3cosx. ...
calculus - A region is bounded by the function y=2x^2+3 and the x-axis over the ...

Search
Members