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A 1200 kg car pushes a 2100 kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N . What is the magnitude of the force the car applies to the truck?

What is the magnitude F_ct of the force that the car exerts on the truck? where the positive y direction is upward, and the positive x direction is to the right, the direction in which F_ct_vec points.

  • Physics - ,

    The 4500 N force on the car's tires accelerates the car and the truck together at a rate
    a = 4500/(1200+2100) = 1.364 m/s
    (assuming the pushed truck offers no resistance).
    The force applied to the truck is is
    Mtruck*a = 2864 N

    The second part of your question seems repetitive. I do not understand your notation.

  • Physics - ,

    u should laearn fysicks atnd then u wi lll ge t ethe anserr

  • Physics - ,


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