Posted by **invy** on Monday, October 31, 2011 at 10:14pm.

a car travels at a constants speed and uses G(x) litres of gas per kilomotre, where x is the speed of the car in kilomotres oer hour and G(x)=(1280+x^2)/(320x)

a>if fuel costs 1.29 per litre, determine the cost function C(x)that expresses the cost of the fuel for a 200KM trip as a function of the speed.

b>what driving speed will make the cost of fuel equal to 300

c>what driving speed will minimize the cost of fuel for the trip?

- math -
**Steve**, Tuesday, November 1, 2011 at 10:56am
G(x) = 4/x + x/320

(a) C(x) = cost for x km trip

$ = liters * $/liter

liters = L/km * km

C(x) = G(x) * 200 * 1.29

= 258*G(x)

= 258(4/x + x/320) = 1032/x + 258/320 * x

(b) 300 = 1032/x + 258/320 x

96000x = 330240 + 258x^2

x = 3.4 or 368.6 ???!!!??

(c) C' = -1032/x^2 + 0.80625

C' = 0 at x = 35.8 km/h

If my math is right, that's some weird numbers...

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