what mass of water is required for the formation of 175 grams of carbon monoxide? please show work
You need an equation. Then follow the steps in this example problem. http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the mass of water required for the formation of 175 grams of carbon monoxide, we need to consider the balanced chemical equation for the reaction.
The balanced equation for the formation of carbon monoxide from water and carbon is:
C + H2O → CO + H2
From the equation, we can see that the molar ratio between carbon monoxide and water is 1:1. This means that for every mole of carbon monoxide, we need one mole of water.
Step 1: Calculate the number of moles of carbon monoxide (CO)
Using the molar mass of carbon monoxide (28.01 g/mol), we can determine the number of moles:
moles of CO = mass of CO / molar mass of CO
moles of CO = 175 g / 28.01 g/mol
moles of CO = 6.248 mol
Step 2: Calculate the number of moles of water (H2O)
Since the molar ratio between CO and H2O is 1:1, the number of moles of water will be the same as the number of moles of carbon monoxide:
moles of H2O = moles of CO
moles of H2O = 6.248 mol
Step 3: Calculate the mass of water (H2O)
Using the molar mass of water (18.015 g/mol), we can determine the mass of water:
mass of H2O = moles of H2O × molar mass of H2O
mass of H2O = 6.248 mol × 18.015 g/mol
mass of H2O = 112.51 g
Therefore, approximately 112.51 grams of water is required for the formation of 175 grams of carbon monoxide.
To determine the mass of water required for the formation of 175 grams of carbon monoxide, we need to consider the balanced chemical equation for the reaction.
The chemical equation for the formation of carbon monoxide (CO) from water (H2O) can be represented as follows:
2H2O + 2CO → 2CO2 + 4H2
From the equation above, we can see that for every 2 moles of carbon monoxide produced, we need 2 moles of water.
To find the molar mass of carbon monoxide (CO), we add the atomic masses of carbon (C) and oxygen (O) which gives us:
C = 12.01 g/mol
O = 16.00 g/mol
Molar Mass of CO = C + O
= 12.01 + 16.00
= 28.01 g/mol
Now, let's calculate the number of moles of carbon monoxide:
Moles of CO = Mass of CO / Molar Mass of CO
= 175 g / 28.01 g/mol
≈ 6.247 mol
Since the balanced equation tells us that every 2 moles of CO requires 2 moles of water, the number of moles of water required will be half of the number of moles of carbon monoxide produced.
Moles of H2O = (1/2) * Moles of CO
= (1/2) * 6.247 mol
≈ 3.1235 mol
Now, we need to convert the moles of water to grams. The molar mass of water (H2O) is:
Molar Mass of H2O = 2(H) + O
= 2(1.008 g/mol) + 16.00 g/mol
= 18.02 g/mol
Mass of H2O = Moles of H2O * Molar Mass of H2O
= 3.1235 mol * 18.02 g/mol
≈ 56.36 g
Therefore, approximately 56.36 grams of water would be required for the formation of 175 grams of carbon monoxide.