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Calculus 1

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Use Newton's method to approximate the root of the equation x^3+x+2=0 with initial guess x1=-1 gives:

  • Calculus 1 - ,

    Using trig get:

    Xn+1 = Xn - Yn/Y'n
    where
    Y = x^3 + x + 2
    Y' = 3x^2 + 1
    for x = -1
    Y = -1-1+2 = 0 well how embarrassing, we guessed it exactly
    Y' = 4 irrelevant

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