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March 30, 2015

March 30, 2015

Posted by **Olivia** on Monday, October 31, 2011 at 7:07pm.

- Calculus 1 -
**Damon**, Monday, October 31, 2011 at 7:23pma and b are lengths

A = 220 = a * b so a = 220/b

cost = 2(6a) + 1 (6b) + 1(13b)

cost = c = 12 a + 19 b

c = 12(220/b)+19 b

dc/db = 0 at max or min = 12(-220/b^2) + 19

220(12) = 19 b^2

solve for b and a

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