Posted by -Untamed- on Monday, October 31, 2011 at 6:40pm.
try
(x-5)(4x-3)
Now to do that I solved the quadratic equation (google that)
I found for solutions
x = 5 and x = 6/8 which is 3/4
so
(x-5)(x-3/4) = 0 is solution
I can multiply both sides by 4 to get rid of the faction
(x-5)(4x-3) = 0
How did you get that using the criss cross method?
solving for zeros with quadratic equation:
[ -23 +/- sqrt (529 - 240) ]/8
[-23+/-17]/8
-40/8 and -6/8
I never heard of the criss cross method. I used the quadratic equation to solve for zeros of the quadratic expression.
5 and 4 make 20
1 and 3 make 3
Do it backwards from my solution and you will see :)
For the criss cross method, Im supposed to find two numbers that multiply to get 4x^2. And those were 2x and 2x. Then, Im supposed to find two numbers that multiply to give me 15, which was either 15 and 1 or 3 and 5. I used both, by criss crossing 2x to 3 and 2x to 5. That gave me 10x and 6x which does not give me 23x, and same with using 15 and 1, that just gave me 28, -28, etc.
Nevermind, I think I got it. Thanks for showing me the Quadratic way.
But 1 * 4 = 4 as well :)
b-6b+8
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