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October 22, 2014

October 22, 2014

Posted by **Monique** on Monday, October 31, 2011 at 5:34pm.

a.0.668

b.0.858

c.0.908

d.0.995

- Statistics -
**PsyDAG**, Monday, October 31, 2011 at 6:16pmZ = (Sample mean-Pop. mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

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