Homework Help: physics

Posted by amy on Monday, October 31, 2011 at 11:54am.

to push a 25 kg crate up a 27 incline, a worker exerts a force of 120 N, parallel to the incline. As the crate slides 3.6 m, how much work is done on the crate by a) the worker b) force of gravity c) normal force

physics - Henry, Wednesday, November 2, 2011 at 4:29pm
Wc = mg = 25kg * 9.8N/kg = 245N. = Weight of crate.

Fc = 245N @ 27deg.
Fp = 245sin27 = 111.2N.=Force parallel to incline.
Fv = 245cos27 = 218.3N. = Force perpendicular to incline = Normal.

a. W = Fd = 120 * 3.6 = 432J.

b. W = Fc*d=Fc*h=245 * 3.6sin27 = 400J.

c. W=Fv * d = 218.3 * 3.6sin27 = 357J.
physics - mara tuazon, Friday, October 12, 2012 at 6:24am
i would like to say thank you for this wonderful problem .. this same problem appeared at my homework and it was a big help

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