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A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.3 kg. The center of mass of the pendulum rises a vertical distance of 9.7 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

....I'm getting an answer of 3002.05m/s and it's saying that my answer is wrong.

  • Physics - ,

    From conservation of energy followuing impact,
    gH = V'^2/2
    V' = 1.3795 m/s
    That is the velocity of the block when it starts swinging.

    From conservation of momentum prior to the impact,
    mV = (m+M)V'

    V = (3.3048/0.0048)*1.3795 = 949.8 m/s

    That should be rounded to 950 m/s

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