Posted by **Eli** on Monday, October 31, 2011 at 8:53am.

A mettallurgist decided to make a special alloy. He melted 30 grams of Au(Gold) with 30 grams of Pb. This melting process resulted to 42 grams of an Au-Pb alloy and some leftover Pb. This scientist wanted to make 420 grams of this alloy with no leftovers of any reactants. how much of Au and Pb would he need to use in order to have the desired grams of the alloy?

Au + Pb = Au-Pb left over

- Chemistry -
**Dr Russ**, Monday, October 31, 2011 at 9:00am
Not a great deal of chemistry here as it is by proportion.

He melted 30 grams of Au (gold) with 30 grams of Pb. This melting process resulted to 42 grams of an Au-Pb alloy and some leftover Pb.

So assume all the gold is incorporated then (42-30) g of lead used, which is 12 g.

Thus for each 42 g of alloy, 30 g of gold and 12 g of lead are needed.

Hence for 420 g (42 g x 10), 300 g (30 g x 10) of gold and 120 g (12 g x 10)of lead are needed.

## Answer this Question

## Related Questions

- algebra - assume that a jeweler needs 80 grams of an alloy that is 30% gold. He ...
- College Algebra - Chemistry - A goldsmith has two gold alloys. The first alloy ...
- algebra - A goldsmith has two gold alloys. The first alloy is 30% gold; the ...
- Algebra - A goldsmith has two gold alloys. The first alloy is 20% gold; the ...
- algebra - A chemist has x grams of an alloy that is 20% silver and 10% gold, and...
- Algebra - solve linear equation-an alloy of metal is 25% copper. Another alloy ...
- math - An alloy of metals is 25% copper. Another alloy is 50% copper. How much ...
- PLZ ANSWER CHEM QUESTION - a chemist reacted 64 grams of Ru with O2. This ...
- physics - The energy given off by 300 grams of an alloy as it cools through 50°C...
- chemistry - A 14 karat gold alloy contains 58% m/m gold. How much of this alloy ...