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November 23, 2014

November 23, 2014

Posted by **Brianna** on Sunday, October 30, 2011 at 11:08pm.

- ****college algebra**** -
**Steve**, Monday, October 31, 2011 at 4:00pmYou want h(h) = h. That is,

3h+4 = h

3(3x+4) + 4 = 3x+4

9x + 12 + 4 = 3x + 4

6x = -12

x = -2

h(-2) = 3(-2) + 4 = -2

Or, using h^{-1}, you could say, recalling that

h^{-1}(h(x)) = x

So, h^{-1}(h(h)) = h^{-1}(h)

h = x

3x+4 = x

2x = -4

x = -2

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