Math
posted by Angel on .
Use the definition of logarithm to simplify each expression.
log6b(6b)
log8b((8b)^6)
log12b((12b)^11)

By definition, log_{n}n = 1
log_{6b}6b = 1
log_{8b}(8b)^{6} = 6log_{8b}8b = 6
log_{12b}(12b)^{11} = 11log_{12b}12b = 11