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December 20, 2014

December 20, 2014

Posted by **Angel** on Sunday, October 30, 2011 at 9:44pm.

log6b(6b)

log8b((8b)^6)

log12b((12b)^-11)

- Math -
**Steve**, Monday, October 31, 2011 at 12:25pmBy definition, log

_{n}n = 1

log_{6b}6b = 1

log_{8b}(8b)^{6}= 6log_{8b}8b = 6

log_{12b}(12b)^{-11}= -11log_{12b}12b = -11

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