Friday

March 6, 2015

March 6, 2015

Posted by **mehak** on Sunday, October 30, 2011 at 9:38pm.

- calculus -
**Steve**, Monday, October 31, 2011 at 12:21pmy = 23 - x

^{2}

y' = -2x

So, we want all points where the line through (x,y) and (10,26) has slope -2x

(y-26)/(x-10) = -2x

(23-x^{2}- 26)/(x-10) = -2x

-3 - x^{2}= -2x(x-10)

-3 - x^{2}= -2x^{2}+ 20x

x^{2}- 20x - 3 = 0

x = -0.149 or 20.149

At those values for x, we have

(x,y) = (-0.149,22.978) and (20.149,-382.982)

y' = 0.290 and -40.298

the line through (-0.149,22.978) and (10,26) has slope 3.022/10.149 = 0.29

the line through (20.149,-382.982) and (10,26) has slope 408.982/-10.149 = 40.298

Look slike those are our lines.

**Answer this Question**

**Related Questions**

Calculus - Sketch a graph of the parabola y=x^2+3. On the same graph, plot the ...

Calculus - Given the function y=(x^2-5/x+3), answer the following questions. a) ...

Math- calculus - Given f(x) = x ^ 3 - x ^ 2 -4x +4 Find the zeros of f. Write an...

calculus - If the graph of f passes through the point (1, 0) and the slope of ...

Calculus - 1. Given the function f defined by f(x) = x^3-x^2-4X+4 a. Find the ...

calculus - let f be the function f(x) = x^3 + 3x^2 - x + 2 a. the tangent to the...

Math--Calculus - Let y = f(x) be the continuous function that satisfies the ...

Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...

Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...

Mathamatics - This question concerns the straight line that passes through the ...