Saturday

April 19, 2014

April 19, 2014

Posted by **nully** on Sunday, October 30, 2011 at 8:15pm.

A ride in an amusement park consists of a cylindrical chamber that rotates around a vertical axis as shown in the diagram below. When the angular velocity is sufficiently high, a person leaning against the wall can take his or her feet off the floor and remain "stuck" to the wall without falling.

Construct an expression for the minimum angular velocity that the ride could rotate at such that the person remains stuck to the wall. Use the following Use the following when entering your symbolic expression:

m : for the mass of the person

g : for the gravitational field strength near the surface of the earth

r : the radius of the cylindrical chamber (from the center to the walls)

mu : for the coefficient of friction between the person's back and the wall

pi : for π = 3.141592654...

2. Relevant equations

|FN| = mv2/r the inward normal force

|Fs| = μs|FN|maximum force of static friction

Fs| = mg

3. The attempt at a solution

I thought this was the answer but it is not correct.

v = sqrt((g*r)/mu)

which =1.98

but the right answer is 1.25 rad/sec and linear=6.25m/s

I dont know where i am going wrong please help

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