Monday

October 20, 2014

October 20, 2014

Posted by **Reonea** on Sunday, October 30, 2011 at 7:33pm.

Speed of dot _______ = mph.

- Calculus -
**bobpursley**, Sunday, October 30, 2011 at 7:40pmdraw the triangle

s=Searchlight postion

8= distance wall is away.

x= distance from the perpendicular to the light to the position of the beam, so that

TanTheta=x/8

take derivative w/respect to time

d(tanTheta)=1/8 dx/dt

sec^2 theta * dtheta/dt=1/8 dx/dt

you are given theta, given dtheta/dt (4PI), find dx/dt

- Calculus -
**H H Chau**, Friday, August 22, 2014 at 7:01pmdθ/dt=2 rev/min=4π rad/min

dx/dt=8*(sec^2(π/5))*8π=154 miles/min=9216 mph

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