A ball of mass 1kg is thrown upwards and reaches a maximum height of 4m.Calculate the work done by the force of gravity during vertical displacement.Take g=10m/s
Since
Work done is change in kinetic energy.
So,W=Ke m=1kg
and Ke=mgh g=-10m\s2
=1x-10x4 h=4m
Ans =-40Nm
To calculate the work done by the force of gravity, we need to determine the vertical displacement of the ball and multiply it by the gravitational force acting on the ball.
The formula for work is given by W = F * d * cos(θ), where W is the work done, F is the force applied, d is the displacement, and θ is the angle between the force and the direction of displacement.
In this case, the force of gravity is acting in the opposite direction to the displacement of the ball, so the angle θ is 180 degrees. Therefore, cos(θ) = -1.
The gravitational force acting on the ball, F = mass * gravitational acceleration, where mass = 1kg and the gravitational acceleration is given as g = 10m/s². So F = 1kg * 10m/s² = 10N.
The displacement, d, is given as 4m, the maximum height reached by the ball.
Now we can calculate the work done by the force of gravity:
W = -10N * 4m * (-1)
= 40Nm
= 40 Joules
Thus, the work done by the force of gravity during this vertical displacement is 40 Joules.
work done = change in potential energy
m g h = 1 * 10 * 4 Joules