Posted by **julez** on Saturday, October 29, 2011 at 8:16pm.

Find the real and complex zeros of the following function.

f(x)=x^3-3x^2+25x+29

- algebra -
**drwls**, Saturday, October 29, 2011 at 8:40pm
x = -1 is one root, as you can easily verify by inspection. That means that (x +1) is a factor of the polynomial.

Divide x^3-3x^2+25x+29 by x+1 (using polynomial long division) to get a second order polynomial, from which you can get the other roots easily, using the quadratic formula. They will be complex in this case.

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