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Posted by on Saturday, October 29, 2011 at 7:34pm.

Solve the following equation in the real number system. Please show all of your work.
2x^3-3x^2-14x+15=0

  • college algebra - , Saturday, October 29, 2011 at 7:56pm

    I can see right off that x = 1 works
    2-3-14+15 = 0 sure enough
    so divide by (x-1)--> 2x^2-x-1
    (2x+1)(x-1)
    so x = 1 again and x = -1/2

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